(1/4)^m-7=16

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Solution for (1/4)^m-7=16 equation: 



(1/4)^m-7=16

We move all terms to the left:

(1/4)^m-7-(16)=0



Domain of the equation: 4)^m!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(+1/4)^m-7-16=0

We add all the numbers together, and all the variables

(+1/4)^m-23=0

We multiply all the terms by the denominator


(+1-23*4)^m=0

We add all the numbers together, and all the variables

(-91)^m=0

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